9p^2=-42p-24

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Solution for 9p^2=-42p-24 equation:



9p^2=-42p-24
We move all terms to the left:
9p^2-(-42p-24)=0
We get rid of parentheses
9p^2+42p+24=0
a = 9; b = 42; c = +24;
Δ = b2-4ac
Δ = 422-4·9·24
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-30}{2*9}=\frac{-72}{18} =-4 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+30}{2*9}=\frac{-12}{18} =-2/3 $

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